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Q.

An enzyme contains $2 %$ of sulphur. The molecular weight of the enzyme is $6400 g$ . The sulphur atoms present in the enzyme molecule is $2x$ . What is $‘ x ’$ ?

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Detailed Solution

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100g of enzyme = 2g of Sulphur

6400g of enzyme = x

$x = \frac{2 \times 6400}{100} = 128 g o f s u l p h u r$

Number of Sulphur atoms $= \frac{w e i g h t}{G r a m a t o m i c w e i g h t} = \frac{128}{32} = 4$

$∴ 2 x = 4 \Rightarrow x = 2$

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An enzyme contains 2% of sulphur. The molecular weight of the enzyme is 6400g. The sulphur atoms present in the enzyme molecule is 2x. What is ‘x’?