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An equilateral prism deviates a ray through $45 °$ for two angles of incidence differing by $20 °$ . The angles of incidence are :

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$60^{\circ}$

$42^{0} 32'$

$62^{\circ} 30^{'}$

$61^{\circ}$

answer is B, C.

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Detailed Solution

$\begin{array}{l} δ = i_{1} + i_{2} - A \\ 45^{\circ} = i_{1} + i_{2} - 60^{\circ} \\ i_{1} + i_{2} = 105^{\circ} \\ i_{1} - i_{2} = 20^{\circ} \\ or 2 i_{1} = 125^{\circ} \\ i_{1} = 62^{\circ} 30^{'} and i_{2} = 42^{\circ} 30^{'} \end{array}$

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