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Q.

An equilateral triangle is Inscribed in parabola $y^{2} = 4 ax$ whose one vertex is at origin then length of side of triangle

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a

$4 \sqrt{3} a$

b

$8 \sqrt{3} a$

c

$2 \sqrt{3} a$

d

$6 \sqrt{3} a$

answer is B.

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Detailed Solution

$y^{2} = 4 ax$

$OA = 4 acosecθcotθ = 4 a (2) (\sqrt{3}) = 8 a \sqrt{3}$

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