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Q.

An excess of AgNO3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgNO3 precipitated would be:

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a

0.002

b

0.001

c

0.003

d

0.01

answer is B.

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Detailed Solution

AgNO3+CrH2O4Cl2ClAgClCrH2O4Cl2NO3 millimole M=n×1000Vn=0.01×1001000=0.001 moles 
So, 0.001 moles of AgCl formed. 

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