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An experiment is performed to determine the I-V (Current & Voltage) characteristics of a Zener diode, which has a protective resistance of R=100 $Ω$ , and diode has maximum power of dissipation rating of 1W. The minimum voltage range of the DC source in the circuit is:

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0-12V

0-8V

0-24V

0-5 V

answer is B.

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Detailed Solution

$∵ P = 1 W, R = 100 Ω$ ,

$P = i^{2} R \Rightarrow 1 = i^{2} 100 \Rightarrow i = 0.1 A$

$V = i R + V_{D} \Rightarrow V_{D} = V - i R = V - i 100$

$P o w e r d i s s i p a t i o n d i o d e = P = i V_{D} \Rightarrow 1 = i (V - i 100) \Rightarrow 100 i^{2} - V i + 1 = 0$

$F o r r e a l v a l u e s o f c u r r e n t, V^{2} - 4 (100) (1) \geq 0 \Rightarrow V \geq 20 V$

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