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Q.

An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore (without taking into consideration the time they stop in intermediate stations). If the average speed of the express train is 11 km/hr more than that of the passenger train, find the average speed of the two trains.


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a

Speed of passenger train = 31 km/hr, speed of express train = 42 km/hr

b

Speed of passenger train = 33 km/hr, speed of express train = 44 km/hr

c

Speed of passenger train = 43 km/hr, speed of express train = 54 km/hr

d

None of these 

answer is B.

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Detailed Solution

Concept- In this given question we have given the distance and the difference of speed. By using these two we will calculate the average speed of both trains.
According to the question, sum of the distance between of both train is Question Imageand the speed of the train is Question Imagemore than on another train.
So, we will assume that
Average speed of the  passenger trainQuestion ImageQuestion ImageAverage speed of express trainQuestion ImageQuestion ImageQuestion ImageNow we will put the value in above equation
Time taken by pass. train is equal to Question ImageTime taken by exp. train is equal to Question Image   As it’s given
Time taken by exp. Train + time taken by pass. train Question ImageQuestion Image Question ImageAs x cannot be negative we will take x as a 33.
So the average speed of a passenger train is 33 km/hr.
As average speed of express train is (x+11)km/hr
=33+11
=44 km/hr.
Hence,  the correct answer is option 2.
 
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