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An ice block of volume ‘V’ placed in an artificial satellite. When ice melts in to water then its surface area becomes $4 π c m^{2} .$ (Assume density of ice and water are equal); then V is ______ cc

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$\frac{4}{3}$

$\frac{2 π}{3}$

$\frac{2}{3}$

$\frac{4 π}{3}$

answer is D.

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Detailed Solution

When there is no gravity due to surface tension the water will acquire a shape of sphere.

So, $A = 4 π r^{2} \Rightarrow r = 1 cm$

$∴ V = \frac{4}{3} {πr}^{3} = \frac{4 π}{3}$

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