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An ice cube at 0.00° C is placed in 200g of distilled water at 25.00° C. The final temperature after the ice is completely melted is 5.00° C. What is the mass of the ice cube?
$(Δ H_{fus} = 340 \cdot J \cdot g^{- 1}, C_{p} = 4.18 J \cdot g^{- 1} \cdot^{\circ} C^{- 1})$

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50.0 g

46.3 g

800 g

23.6 g

answer is B.

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Detailed Solution

$\begin{array}{l} m \times 340 + m \times 4.18 (T - 0) = 200 \times 4.18 \times (25 - T) \\ T = 5 \\ 360.9 \times m = 16720 \\ m = 46.32 g \end{array}$

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