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Q.

An ideal choke takes a current of 8A when connected to an a.c source of 100 volt and 50 Hz. A pure resistance under the same conditions takes a current of 10A. If two are connected in series to on a.c. Supply to 100V and 40 Hz, then the current in the series combination of above resistor and inductor is

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a

10A

b

8A

c

$5 \sqrt{2} A$

d

$10 \sqrt{2} A$

answer is C.

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Detailed Solution

$\frac{100}{100 πL} = 8; L = \frac{1}{8 π} \frac{100}{R} = 10 R = 10 X_{L} = 10 Z = 10 \sqrt{2}$

I= 5 $\sqrt{2}$ A

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An ideal choke takes a current of 8A when connected to an a.c source of 100 volt and 50 Hz. A pure resistance under the same conditions takes a current of 10A. If two are connected in series to on a.c. Supply to 100V and 40 Hz, then the current in the series combination of above resistor and inductor is