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Q.

An ideal coil of 10 henry is joined in series with a resistance of 5 ohm and a battery of 5 volt. Two second after joining , the current flowing (in ampere) in the circuit will be

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a

e-1

b

1-e-1

c

e

d

1- e

answer is B.

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Detailed Solution

i=i01−e−RLt ⇒i=551−1e=1-e-1

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