An ideal fluid flows in the pipe as shown in the figure. The pressure in the fluid at the bottom P₂ is the same as it is at the top P₁ . If the velocity of the top v₁ = 2m/ s . Then the ratio of areas A₁ & A₂ is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

8:1

4:3

4:1

2:1

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Using equation of continuity, we have $v_{2} = \frac{A_{1}}{A_{2}} v_{1}$
From Bernoulli’s theorem,
$P_{1} + {ρgh}_{1} + \frac{1}{2} {ρv}_{1}^{2} = P_{2} + {ρgh}_{2} + \frac{1}{2} {ρv}^{2}_{2}$

$\Rightarrow g (h_{1} - h_{2}) = \frac{1}{2} (v_{2}^{2} - v_{1}^{2})$

$\Rightarrow 60 = (\frac{A_{1}^{2}}{A_{2}^{2}} - 1) v_{1}^{2}$

$\Rightarrow \frac{A_{1}}{A_{2}} = \frac{4}{1}$

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!