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An ideal gas at $13^{0} C$ is heated to double Its volume at constant pressue find the final temperature of the gas in is_____⁰C

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answer is 299.

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Detailed Solution

$t_{1} = 13^{0} C, T_{1} = 13 + 273 = 286 K$

Intial volume v₁=v final volume v₂=2v

Final temperature –t₁=?

$\frac{v_{1}}{t_{2}} = \frac{v_{2}}{t_{2}} \Rightarrow T_{2} = \frac{v_{2}}{v_{1}} T_{1} = \frac{2 v}{v} \times 286 = 572 k .$

Final temperature

$t_{2} = 572 - 273 = 299^{0} C$

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