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An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram.
If $Q_{1}, Q_{2}, Q_{3}$ indicate the heat absorbed by the gas along the three processes and $△ U_{1}, △ U_{2}, △ U_{3}$ indicate the change in internal energy along the three processes respectively, then

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$Q_{1} = Q_{2} = Q_{3}$ and $△ U_{1} = △ U_{2} = △ U_{3}$

$Q_{3} > Q_{2} > Q_{1}$ and $△ U_{1} = △ U_{2} = △ U_{3}$

$Q_{1} > Q_{2} > Q_{3}$ and $△ U_{1} = △ U_{2} = △ U_{3}$

$Q_{3} > Q_{2} > Q_{1}$ and $△ U_{1} > △ U_{2} > △ U_{3}$

answer is A.

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Detailed Solution

$Q = △ U + W W = A r e a u n d e r P - V o u v e ∴ W_{1} > W_{2} > W_{3}; △ U_{1} = △ U_{2} = △ U_{3} ∴ Q_{1} > Q_{2} > Q_{3}$

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