An ideal gas has specific heat capacity at constant pressure 11/10R. If one mole of this ideal gas at 125⁰C does 83J of work adiabatically, then final temperature of the gas would be (R = 8.3 J/K mole)

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25⁰ C

75⁰ C

100⁰ C

50⁰ C

answer is A.

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Detailed Solution

$\begin{array}{l} C_{p} = \frac{11}{10} R C_{v} = C_{p} - R = \frac{R}{10} γ = \frac{C_{p}}{C_{v}} \\ w = \frac{nR (T_{1} - T_{2})}{γ - 1} \end{array}$

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