An ideal gas initially at pressure 1 bar is being compressed from 30 m³ to 10 m³ volume and its temperature decreases from 320 K to 280 K, then find the value of final pressure of the gas.

Given, initial pressure of ideal gas,
                          p₁ = 1 bar = $1 {\mathrm{NM}}^{-2}$
Initital volume, V₁ = 30 m³
Final volume, V^₂ = 10 m³
Initial temperature, T₁ = 320 K
Final temperature, T₂ = 280 K
Final pressure of gas, p₂ = ?

From ideal gas equation, 

                            $\frac{p_1{V}_1}{T_1}=\frac{p_2{V}_2}{T_2}$

$\Rightarrow$                      $\frac{1\times 30}{320}=\frac{p_2\times 10}{280}$

$\Rightarrow$                              p₂ = 2.625 bar