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An ideal gas is allowed to expand in a well insulated container against a constant external pressure of 5 atm from an initial volume of 8 litres to final volume of 10litres. Change in internal energy is

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+1010 J

-1505 J

-1010 J

1505 J

answer is C.

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Detailed Solution

$W_{irr} = - P_{ext} (v_{f} - v_{i}) = - 5 (10 - 8) = - 10 lit - atm W_{irr} = - 10 (101 J) = - 1010 J ΔU = q + w q = 0, for insulated vessel Δu = w = - 1010 J$

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