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An ideal gas is expanded so that amount of work done by it is equal to the decrease in internal energy. The gas undergoes the process TV^2/5 = constant the adiabatic compressibility of gas when pressure is P, is:

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7/5P

5/7P

2P/5

7P/5

answer is B.

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Detailed Solution

$T V^{2 / 5} = cons$

$P V^{7 / 5} = cons$

$γ = 7 / 5$

$C = \frac{1}{B} = \frac{1}{γ_{P}} = \frac{1}{\frac{7}{5} P} = \frac{5}{7 P}$

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