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An ideal gas is initially at temperature T and volume V. Its volume is increased by $∆ V$ due to an increase in temperature $∆ T$ , pressure remaining constant. The quantity $δ = \frac{∆ V}{(V ∆ T)}$ varies with temperature as:

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answer is C.

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Detailed Solution

At constant pressure, $V \propto T$
$\Rightarrow \frac{∆ V}{V} = \frac{∆ T}{T} So, δ = \frac{∆ V}{V ∆ T} = \frac{1}{T} \Rightarrow δT = constant .$

So, the graph is rectangular hyperbola.

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