Q.

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps ate Q1=5960J,Q2=5585J,Q3=2980JQ4=3645J, respectively. The corresponding works involved are W1=2200J,W2=825J,W3=1100J and W4, respectively. The value of W4 is

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a

1315 J

b

765 J

c

675 J

d

275 J

answer is C.

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Detailed Solution

Q=Q1+Q2+Q3+Q4 =596055852980+3645=1040JW=W1+W2+W3+W4 =22008251100+W4=275+W4

 For a cyclic process, Uf=Uf

         ΔU=UfUi=0

From the first law of thermodynamics,

            Q=ΔU+W1040=0=275+W4  or  W4=765J

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