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Q.

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amount of heat involved four steps are $Q_{1} = 6000 J, Q_{2} = - 5000 J, Q_{3} = - 3000 J a n d Q_{4} = 4000 J$ respectively. If efficiency of cycle is $10 x %$ then find value of x?

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answer is 2.

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Detailed Solution

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$η = \frac{W n e t}{T o t a l heat supplied} = \frac{Q_{1} + Q_{2} + Q_{3} + Q_{4}}{Q_{1} + Q_{4}} = \frac{2000}{10000} \times 100 = 20 % so x = 2$

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An ideal gas is taken through a cyclic thermodynamic process through four steps. The amount of heat involved four steps are Q1= 6000J, Q2= –5000J, Q3= –3000J and Q4= 4000J respectively. If efficiency of cycle is 10x % then find value of x?