An ideal gas is taken through cycle $A\to B\to C\to A$  as shown in figure. If the net heat supplied to the gas is 10J, then the work done by process $B\to C$ is

 An inflores

$\Delta Q=W_{AB}+W_{BC}+W_{CA}+\Delta U$, ($\Delta U$=0 for the complete cycle)

The total work done in the cycle matches the heat added (ΔQ) confirming the calculation:

$\therefore 10=10\left(3-1\right)+W_{BC}+0$

$\therefore W_{BC}=-10J$

Heat added (ΔQ) = 10J, Work done during BC = −10J, Internal energy change (ΔU) = 0 over the complete cycle.