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An ideal gas is taken through the cycle $A \to B \to C \to A$ as shown in the fig. If the net heat supplied to the gas in the cycle is 5J, the work done by the gas in the process $C \to A$ is:

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-5J

-10J

-15J

-20J

answer is A.

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Detailed Solution

${ΔW}_{AB} = 10 (2 - 1) J$

${ΔW}_{BC} = 0$

$From 1^{st} law ΔQ = ΔU + ΔW$
$ΔU = 0$

$ΔQ = {ΔW}_{AB} + {ΔW}_{BC} + {ΔW}_{CA}$

$\Rightarrow 5 = 10 + 0 + {ΔW}_{CA}$

$\Rightarrow {ΔW}_{CA} = - 5 J$

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