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An ideal gas obeys additional law PV² = Constant . Initial temperature of gas is T . If volume of gas is doubled, temperature becomes

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$\frac{T}{4}$

$\frac{T}{2}$

$\sqrt{T}$

answer is C.

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Detailed Solution

PV² = Constant ….(1)
Again, PV = nRT
$P = \frac{nRT}{V}$
So, from (1)
$\frac{nRT}{V} V^{2} = const \Rightarrow VT = const \Rightarrow V \propto \frac{1}{T}$

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