An ideal gas occupies a volume af 2 m3 at a pressure of 3 x 106 Pa. The energy of the gas is

E=32PVor E=3PV2=3×3×106×22=9×106J

An ideal gas occupies a volume af 2 m3 at a pressure of 3 x 106 Pa. The energy of the gas is

E=32PVor E=3PV2=3×3×106×22=9×106J

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An ideal gas occupies a volume af 2 m³ at a pressure of 3 x 10⁶ Pa. The energy of the gas is

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9 x 10⁶ J

3 x 10²J

6 x 10⁴J

10⁸J

answer is A.

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$E= \frac{3}{2} PV$
or $E = \frac{3 PV}{2} = \frac{3 \times 3 \times 10^{6} \times 2}{2} = 9 \times 10^{6} J$

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An ideal gas occupies a volume af 2 m3 at a pressure of 3 x 106 Pa. The energy of the gas is

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An ideal gas occupies a volume af 2 m³ at a pressure of 3 x 10⁶ Pa. The energy of the gas is