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Q.

An ideal gas occupies a volume af 2 m³ at a pressure of 3 x 10⁶ Pa. The energy of the gas is

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a

9 x 10⁶ J

b

3 x 10²J

c

6 x 10⁴J

d

10⁸J

answer is A.

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Detailed Solution

$E= \frac{3}{2} PV$
or $E = \frac{3 PV}{2} = \frac{3 \times 3 \times 10^{6} \times 2}{2} = 9 \times 10^{6} J$

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