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Q.

An ideal gas system undergoes an isothermal process, then the work done during the process is

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a

nRT lnV2V1

b

nRT lnV1V2

c

2nRT lnV2V1

d

2nRT lnV1V2

answer is A.

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Detailed Solution

Let an ideal gas goes isothermally from its initial state (P,V) to the final state (P2,V2), then work done

                  W = V1V2PdV     Taking V = nRT or P = nRTV

Then, W = V1V2nRTVdV = nRTV1V21VdV = nRTlnV2V1

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