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An ideal gas under goes a cyclic process as shown if figure
$Δ U_{B C} = - 5 K J m o l e^{- 1} q_{A B} = 2 K J m o l e^{- 1} W_{A B} = - 5 K J m o l e^{- 1} W_{C A} = 3 K J m o l e^{- 1}$
Heat absorbed by the system during process CA is

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$- 5 K J m o l e^{- 1}$

$+ 5 K J m o l e^{- 1}$

$18 K J m o l e^{- 1}$

$- 18 K J m o l e^{- 1}$

answer is B.

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Detailed Solution

$Δ U_{A B} = d_{A B} + W_{A B} = 2 + (- 5) = - 3 K J / m o l e Δ U_{B C} = - 5 K J / m o l e$

For cyclic process, $Δ U = 0$

$Δ U_{A B} + Δ U_{B C} + Δ U_{C A} = 0 Δ U_{C A} = - Δ U_{A B} - Δ U_{B C} Δ U_{C A} = - (- 3) - (- 5) = 8 K J / m o l Δ U_{C A} = q_{C A} + W_{C A} 8 = q_{C A} + 3 \Rightarrow q_{C A} = + 5 K J / m o l$

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