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Q.

An ideal gas undergoes a cycle process as shown in figure

Question Image

ΔBC=5kJmol1,q AB=2kJmol1;wAB=5kJmol1,WCA=3kjmol1

Heat absorbed by the system during process CA is:

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a

5kJmol1

b

+5kJmol1

c

18kJmol1

d

18kJmol1

answer is B.

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Detailed Solution

Δ BA=q AB+w AB=2+(5)=3kJ/molΔ BC=5kJ/mol

For cyclic process, Δ=0

Δ AB+Δ BC+Δ CA=0 Δ CA=(3)(5)=8kJ/mol Δ CA=q CA+w CA 8=q CA+3q CA=5kJ/mol

Heat absorbed has positive sign.

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