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Q.

An ideal gas was subjected to following process:

n1=2 mole, T1=400K,P1=1atm

→Reversible Isobaricallyn2=2mole,T2=300K,P2=1atm

The work done by the gas is:

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a

+831.4J

b

+1662.8 J

c

-1662.8 J

d

-831.4J

answer is B.

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Detailed Solution

The work done by the gas is

w=−nRΔT=−2×8.314×(300−400)

=+1662.8J

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