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Q.

An ideal gas with adiabatic exponent $γ$ undergoes a process 1→ 2 as shown in the figure, the heat supplied and work done in the process is $Δ$ Q and $Δ$ W respectively. The ratio $Δ$ Q : $Δ$ W is (ρ→density, T→absolute temperature)

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a

$γ : γ - 1$

b

$γ - 1 / γ$

c

$γ - 1$

d

$γ$

answer is A.

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Detailed Solution

Process is isobaric.
$\begin{array}{l} ΔQ = {nC}_{P} ΔT \\ ΔW = nRΔT \end{array}$

$\frac{∆ Q}{∆ W} = \frac{C_{P}}{R} = \frac{C_{P}}{C_{P} - C_{V}} = \frac{γ}{γ - 1}$

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