An ideal gaseous sample at initial state $i\left(P_0,V_0,T_0\right)$ is allowed to expand to volume $2 {\mathrm{V}}_0$ using two different process, in the first process, the equation of process is  $2P{V}^2=K_1$ and in the second process the equation of the process is $PV=K_2$ • Then :

The order of value of work done cannot be compared unless we know the value of ${\mathrm{K}}_1$ and ${\mathrm{K}}_2$.

I st process is not possible.

Value of work done (magnitude) in second process is greater in above expansion irrespective value of ${\mathrm{K}}_1$ and ${\mathrm{K}}_2$ .

Work done in first process will be greater than work in second process (magnitude wise).