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An ideal heat engine has an efficiency $η$ . The coefficient of performance of the engine when driven backward will be

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1- $(\frac{1}{η})$

$η - (\frac{1}{η})$

$(\frac{1}{η}) - 1$

$(\frac{1}{1 - η})$

answer is C.

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Detailed Solution

$η = 1 - \frac{T_{2}}{T_{1}}$

and $ω = \frac{T_{2}}{T_{1} - T_{2}} = \frac{\frac{T_{2}}{T_{1}}}{1 - (\frac{T_{2}}{T_{1}})} = \frac{(1 - η)}{η} = \frac{1}{η} - 1$

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