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An ideal heat engine working between temperatures $T_{1} and T_{2} (T_{1} > T_{2})$ has efficiency $η$ . If both temperatures are lowered by 100K each, The new efficiency of the engine will be

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Greater than $η$

Less than $η$

Greater than or less than $η$ depending upon the nature of working substance.

Equal to $η$

answer is B.

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Detailed Solution

$\begin{array}{l} η = \frac{T_{1} - T_{2}}{T_{1}} \\ η' = 1 - \frac{T_{2} - 100}{T_{1} - 100} = \frac{T_{1} - 100 - (T_{2} - 100)}{T_{1} - 100} = \frac{T_{1} - T_{2}}{T_{1} - 100} > η \end{array}$

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