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Q.

An ideal liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross-section A1 and A2 are v1 and v2 respectively. The difference in the levels of the liquid in the two vertical tubes is h.

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(i) The volume of the liquid flowing through the tube in unit time is A1v1.

(ii) v2-v1=2gh

(iii) v22-v12=2gh

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a

(iii), (ii)

b

(i), (iii)

c

 (i), (ii), (iii)

answer is C.

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Detailed Solution

Volume flow rate =A1v1=A2v2

 

Further, from Bernoulli's theorem,

p1+12ρv12=p2+12ρv22 12ρv22-v12=p1-p2=ρgh v22-v12=2gh

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