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Q.

An ideal liquid is flowing in a cylindrical tube of internal diameter 4 cm with a velocity of 5 m/s. If this tube is connected to another tube of internal diameter 2 cm, then the velocity of the liquid in the second tube will be (in m/s)

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answer is 20.

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Detailed Solution

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According to the equation of continuity,

$A_{2} v_{2} = A_{1} v_{1} Or$

$v_{2} = {(\frac{d_{1}}{d_{2}})}^{2} v_{1} = {(\frac{4}{2})}^{2} \times 5 = 20 m / s$

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