Q.

 An ideal monoatomic gas undergoes a process in which its internal energy U and density ρ vary as Uρ= constant. The ratio of change in internal energy and the work done by the gas is

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a

32

b

23

c

13

d

35

answer is A.

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Detailed Solution

Uρ= constant 

  T1V= constant 

 or   TV

  p= constant 

    ΔUW=ΔUQ-ΔU

=nCyΔTnCpΔT-nCVΔT

=1γ-1=153-1=32

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