An ideal p-n junction diode can withstand currents up to 10 mA under forward bias. The diode has a potential difference of 0.5 V across it which is assumed to be independent of current. What is the maximum voltage of the battery used to forward bias the diode when resistance of 200 $Ω$ is connected in series with it?

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1.25V

2.5V

answer is A.

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Detailed Solution

$\begin{matrix} V = V_{diode} + V_{Resistance} \\ = 0 .5 + I \times R_{R} \\ = 0 .5 + 200 \times 10 \times 10^{- 3} \\ = 0 .5 + 2 = 2 .5 V \end{matrix}$

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