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Q.

An ideal solenoid of cross sectional area 10^-4m2has 500 turns per metre. At the centre of this solenoid, another coil of 100 turns is wrapped closely around it. If the
current in the coil changes from 0 to 2A in 3.14 ms, the emf developed in the second coil is

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a

1 mV

b

3 mV

c

2 mV

d

4 mV

answer is D.

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Detailed Solution

$\begin{array}{l} M = μ \frac{N_{1} N_{2}}{l} . A \\ e = M \frac{Δi}{Δt} = \frac{4 π \times 10^{- 7} \times 500 \times 100 \times 10^{- 4}}{1} \times \frac{2}{3 .14 \times 10^{- 3}} \\ = 40 \times 10^{- 7} \\ = 4 \times 10^{- 3} v = 4 mV \end{array}$

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