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Q.

An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The rnass is released with the spring initially unstretched. Then the maximum extension in the spring is

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a

4 MgK

b

2 MgK

c

MgK

d

Mg2K

answer is B.

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Detailed Solution

Let x be the maximum extension of the spring. From energy conservation

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Loss in gravitational potential energy = Gain in potential energy of spring

Mgx = 12Kx2

⇒x = 2MgK

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