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An ideal transformer with purely resistive load operates at 12 kV on the primary side. It supplies electrical energy to a number of nearby houses at 120 V. The average rate of energy consumption in the houses served by the transformer is 60 kW. The value of resistive load (R_s) required in the secondary circuit will be _______ $m Ω .$

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answer is 240.

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Detailed Solution

$\begin{array}{l} V_{P} = 12 k V; V_{S} = 120 V \\ P_{S} = 60 k W; P_{S} = \frac{V_{S}^{2}}{R_{S}}; 60 \times 10^{3} = \frac{120 \times 120}{R_{S}} \\ R_{S} = 240 mΩ \end{array}$

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