An impulse "I" given to a body changes its velocity from "v1" to " v2". The increase in the kinetic energy of the body is given by

Impulse= m(v2-v1)Change in Kinetic energy = 12mv22-12mv12=12mv2+v1.v2-v1=12.I.(v2+v1)

An impulse "I" given to a body changes its velocity from "v1" to " v2". The increase in the kinetic energy of the body is given by

Impulse= m(v2-v1)Change in Kinetic energy = 12mv22-12mv12=12mv2+v1.v2-v1=12.I.(v2+v1)

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An impulse "I" given to a body changes its velocity from "v₁" to " v₂". The increase in the kinetic energy of the body is given by

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$I (v_{1} - v_{2})$

$I (v_{1} + v_{2}) / 2$

$I (v_{1} - v_{2}) / 2$

$I (v_{1} + v_{2})$

answer is B.

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Detailed Solution

Impulse= $m (v_{2} - v_{1})$

Change in Kinetic energy = $\frac{1}{2} {mv}_{2}^{2} - \frac{1}{2} {mv}_{1}^{2} = \frac{1}{2} m [(v_{2} + v_{1}) . (v_{2} - v_{1})] = \frac{1}{2} . I . (v_{2} + v_{1})$

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