An impulse I given to a body changes its velocity from v1 to v2 . Increase in kinetic energy of body is

I=mv2−v1ΔKE=12mV22−V12=12mV2−V1V2+V1 =12(I)V2+V1

An impulse I given to a body changes its velocity from v1 to v2 . Increase in kinetic energy of body is

I=mv2−v1ΔKE=12mV22−V12=12mV2−V1V2+V1 =12(I)V2+V1

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An impulse I given to a body changes its velocity from v₁ to v₂ . Increase in kinetic energy of body is

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$I (v_{1} + v_{2})$

$I (v_{2} - v_{1})$

$\frac{I (v_{1} + v_{2})}{2}$

$\frac{I (v_{2} + v_{1})}{2}$

answer is C.

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$\begin{array}{l} I = m (v_{2} - v_{1}) \\ \begin{aligned} ΔKE & = \frac{1}{2} m (V_{2}^{2} - V_{1}^{2}) = \frac{1}{2} m (V_{2} - V_{1}) (V_{2} + V_{1}) \\ = \frac{1}{2} (I) (V_{2} + V_{1}) \end{aligned} \end{array}$

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An impulse I given to a body changes its velocity from v₁ to v₂ . Increase in kinetic energy of body is