An impulse "I" given to a body changes its velocity from "v1 to v2". The increase in the kinetic energy of the body is given by

ΔKE=12mv22−v12=12mv2+v1v2−v1=I2v2+v1 ∵I=mv2−v1]

An impulse "I" given to a body changes its velocity from "v1 to v2". The increase in the kinetic energy of the body is given by

ΔKE=12mv22−v12=12mv2+v1v2−v1=I2v2+v1 ∵I=mv2−v1]

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An impulse "I" given to a body changes its velocity from "v₁ to v₂". The increase in the kinetic energy of the body is given by

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$I (v_{1} + v_{2})$

$I (v_{1} + v_{2}) / 2$

$I (v_{1} - v_{2})$

$I (v_{1} - v_{2}) / 2$

answer is B.

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$\begin{array}{l} ΔKE = \frac{1}{2} m (v_{2}^{2} - v_{1}^{2}) = \frac{1}{2} m (v_{2} + v_{1}) (v_{2} - v_{1}) \\ = \frac{I}{2} (v_{2} + v_{1}) [∵ I = m (v_{2} - v_{1})] \end{array}$

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An impulse "I" given to a body changes its velocity from "v1 to v2". The increase in the kinetic energy of the body is given by

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An impulse "I" given to a body changes its velocity from "v₁ to v₂". The increase in the kinetic energy of the body is given by