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An inclined track ends in a circular loop of diameter ‘D’. From what height on the track a particle should be released so that it completes that loop in the vertical plane?

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a
5D2
b
2D5
c
5D4
d
4D5

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detailed solution

Correct option is C

To follow complete circular path, Minimum velocity at lowermost point of the vertical path is,v=5gR =5gD2

using conservation of mechanical energy,
12mv2=mgh

12m5gD2=mgh h=5D4

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