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An inductance coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watts, when a steady current of 4 amperes is passed through it. Find the time constant of the circuit when the coil is joined across a battery

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0.4 s

answer is A.

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Detailed Solution

$\begin{array}{l} E = \frac{1}{2} {LI}^{2} L = 4 H, P = i^{2} R \\ 320 = (4^{2}) R \Rightarrow R = 20 \\ Υ = \frac{L}{R} = \frac{4}{20} = \frac{1}{5} = 0 .2 \sec \end{array}$

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