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An inductance of $(\frac{200}{π}) m H$ a capacitance of $(\frac{1}{π}) m F$ and a resistance of 10 ohm are connected in series with an ac source of 220 V, 50 Hz. The phase angle of the circuit is

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$\frac{π}{6}$

$\frac{π}{4}$

$\frac{π}{3}$

$\frac{π}{2}$

answer is C.

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Detailed Solution

$P h a s e a n g l e φ i s \tan^{- 1} (\frac{X_{L} ~ X_{C}}{R}) h e r e X_{L} = L ω = (\frac{200}{π}) 100 π x 10^{- 3} = 20 o h m X_{C} = \frac{1}{C ω} = (10^{3} π) x (\frac{1}{100 π}) = 10 o h m R = 10 o h m$

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