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Q.

An inductor 20 mH, a capacitor 100  μF and a resistor 50 Ω are connected in series across a source of emf.V = 10 sin(314t) . The power loss in the circuits is -----------W.

(Round off to nearest integer)

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Detailed Solution

XL=ωL=314×20×10-3=6.28Ω

XC=1ωC=31.8Ω

Z=R2+XC-XL2=56.1Ω

 Power loss,  Pavg=V02V0Z2RZ=0.79 W

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