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An inductor of inductance 100 mH is connected in series with a resistance, a variable capacitance and an AC source of frequency 2.0 kHz. What should be the value of the capacitance ( nearly in nF ) so that maximum current may be drawn into the circuit?

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answer is B.

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Detailed Solution

This is an LCR series circuit. The current will be maximum when the net reactance is zero.

For this, $\frac{1}{ωC} = ωL$

$\Rightarrow$ $C = \frac{1}{ω^{2} L} = \frac{1}{4 π^{2} \times {(2.0 \times 10^{3} s^{- 1})}^{2} (0.1 H)} = 63 nF$

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