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Q.

An inductor of inductance 100mH is connected in series with a resistance, a variable capacitance and an AC source of frequency 2.0 kHz. the value of the capacitance so that maximum current may be drawn into the circuit.

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a

50 nF

b

60 nF

c

63 nF

d

79 nF

answer is C.

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Detailed Solution

Given L=100mH, f=2kHz,  C=?

f=12πLC⇒c=14π2f2L

=14π2×4×106×100×10−3

=116×106

=0.0625×10−6

=62.5nF ≈63nF

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