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Q.

An inductor of inductance ‘L’ in series with resistance R is connected to an ideal battery of emf V0 at t = 0. The maximum power developed across the inductor during growth of current is

 

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a

V023R

b

V02R

c

V024R

d

Zero

answer is B.

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Detailed Solution

Question Image

i2R+P=V0i

⇒i2R-V0i+P=0

For i to be real,  V02≥4PR

∴ Pmax=V024R

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