An inductor $(L = 100 m H)$ , a resistor $(R = 100 Ω)$ and a battery $(E = 100 V)$ are initially connected in series as shown in the figure. After a long time the battery is disconnected by short circuiting the points A and B. The current in the circuit 1 ms after the short circuit is (in A)

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0.1

1/e

answer is D.

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Detailed Solution

Steady current state, $i_{0} = \frac{E}{R} = 1 A$

Time constant, $t = \frac{L}{R} = 1 m s$

After one time constant or 1 ms, current will be $\frac{1}{e}$ times $i_{0}$ . Or $\frac{1}{e} A$ .

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